A and B are two points on a uniform metal ring whose centre is C. The angle ACB = θ. A and B are maintained at two different constant temperatures. When θ = 180º, the rate of total heat flow from A to B is 1.2 W. When θ = 90º, this rate will be -
Text Solution
Verified by ExpertsThe correct answer is:
C
R total = R for θ = 180 0
Two sections of resistance R/2 each are in parallel R eq = R/4
∴ Rate of heat flow I 1 = 1.2 = 
T/R/4
0.3 = 
θ = 90 0 two sections of resistance R/4 & 3R/4 in parallel R eq
= 
= 
∴ I 2 = 
= 
(0.3) = 1.6 watt
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